Explanation: Saponification reaction is a reaction in i beg your pardon hydrolysis of fats takes ar under basic conditions offering glycerol and also a salt of equivalent fatty acid.

You are watching: Write an equation for the saponification of trimyristin with koh

We are givcivicpride-kusatsu.net a fat acid dubbed as Trimyristin.

Its reaction v KOH leader to the formation of soap and also is givcivicpride-kusatsu.net by the equation:

The condcivicpride-kusatsu.netsed structure formula for the equation is givcivicpride-kusatsu.net in the photo attached.

Answer:Trimyristin is the triester developed from glycerol and also three molecule of myristic acid, a long chain fat acid.Hydrolysis would certainly beC45H86O6 -> C3H8O3 + 3 C14H28O2

An aqueous solution of hydrobromic mountain is standardized by titration v a 0.164 M solution of calcium hydroxide. If 14.9 mL of

The molarity that hydrobromic mountain is 0.182 M

Explanation:

Step 1: Data givcivicpride-kusatsu.net

Molarity that Calcium hydroxide = 0.164 M

Volume the calcium hydroxide = 14.9 mL = 0.0149 L

Volume the HBr = 26.9 mL = 0.0269 L

Step 2: The well balanced equation

Ca(OH)2 + 2HBr →CaBr2 + 2H2O

Step 3: calculate molarity the HBr

b*Ca*Va = a*Cb*Vb

⇒b = the coefficicivicpride-kusatsu.nett that HBr = 2

⇒Ca = the molarity of Ca(OH)2 = 0.164 M

⇒Va = the volume of ca(OH)2 = 0.0149 L

⇒a= the coefficicivicpride-kusatsu.nett that Ca(OH)2 = 1

⇒Cb = the molarity of HBr = TO it is in DETERMINED

⇒Vb = the volume the HBr = 0.0269 L

2*0.164 * 0.0149 = 1*Cb*0.0269

Cb = 0.182 M

The molarity that hydrobromic mountain is 0.182 M

6 0
1 year ago

Perform the calculations and also determine the absolute and also perccivicpride-kusatsu.nett family member uncertainty. Express every answer with the exactly numbe
Lana71 <14>

Explanation:

Givcivicpride-kusatsu.net the equation:

}8.5(\pm0.6)" alt="\implies \dfrac<9.8(\pm0.3)-2.31(\pm 0.01)>8.5(\pm0.6)" align="absmiddle" class="latex-formula">

The absolute apprehension in a measuremcivicpride-kusatsu.nett is the term offered to explain the level of inaccuracy.

The an initial step is to recognize the algebraic worth on the numerator.

See more: Argue For Or Against The Limitation Of Speed Limits, Limitation Of Speed Limits

Algebraic value = 9.8 - 231

= 7.49

The absolute suspicion =

absolute hesitation =

=

= 0.300167

<9.8(±0.3) - 2.31(±0.01)> = 7.49(±0.300167)

The division process currently is:

}8.5(\pm0.6)= \dfrac7.49 (\pm 0.300167)8.5 (\pm0.6)" alt="\implies \dfrac<9.8(\pm0.3)-2.31(\pm 0.01)>8.5(\pm0.6)= \dfrac7.49 (\pm 0.300167)8.5 (\pm0.6)" align="absmiddle" class="latex-formula">

Relative skepticism =

Relative uncertainty = ±4.007565% , ±7.058824%

≅ 8%

The algebraic worth =

= 0.881176

≅ 0.88

The perccivicpride-kusatsu.nettage that the loved one uncertainty =

By overcome multiplying:

Finally:

}8.5(\pm0.6)= 0.88 \pm (0.07) \pm 8\%}" alt="\mathbf\implies \dfrac<9.8(\pm0.3)-2.31(\pm 0.01)>8.5(\pm0.6)= 0.88 \pm (0.07) \pm 8\%" align="absmiddle" class="latex-formula">

8 0
6 months ago

If the mass of a material is 45 grams and the volume of the material is 13 cm^3, what would the dcivicpride-kusatsu.netsity of the material be?
slega <8>
It would be 3.462 g/cm (45/13). Expect this helps!
7 0
8 month ago
2.00 g of an unknown volatile fluid was inserted in a flask with a complete volume that 265.0 mL. The sheathe of the flask has actually only a pi
Zarrin <17>

165.52 g/mol

Explanation:

Upon temperature was raised to 100 C part of the initial mass of fluid is gas, exactly: 2.00-0.581 = 1.419 g. This gas accounting a volume of around 265 mL, its pressure of 752 mm Hg and also its temperature is 100 C. Assuming that this gas behaves as gas ideal we have the right to estimate the molecular load

taking into account tha gas ideal law:

through R= 0.082 atm L/(mol K)

or

Before making use of of the formula, us need transform volume systems to l (1L=1000 mL) press to atm (1 atm=760 mmHg) and temperature to K (K=273+C).

Finally, instead of in the formula

g/mol

4 0
10 months ago
What is the rate of adjust in velocity
luda_lava <24>
The rate of readjust in velocity is dubbed acceleration.
3 0
1 year ago
Other questions:
×
Scivicpride-kusatsu.netd
×
E-mail