Factors that 343 are the integers that division the initial number (i.e. 343) completely. Because 343 is a composite number, it will have much more than 2 factors. Also, 343 is a perfect cube, together that;

343 = 7 x 7 x 7 = 73

By this, we deserve to conclude the 7 is one of the factors of 343. To check, we can divide 343 by 7.

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343 ÷ 7 = 49

Thus, we get a entirety number ~ division. Hence, 7 divides 343 into 49 equal parts.

Now let us learn to discover the various other factors together with pair factors and prime factors. ## How to Find components of 343?

Factors the 343 are the numerical worths that divide the original number, there is no leaving any type of remainder. Therefore, separating 343 by the smallest organic number, 1, will an outcome in the really number. Due to the fact that 343 is an odd number, it cannot be divided by 2 or any type of even numbers.

343 ÷ 1 = 343

343 ÷ 7 = 49

343 ÷ 49 = 7

343 ÷ 343 = 1

Thus, we have the right to conclude that only 1, 7, 49 and 343 space the components of 343.

## Pair determinants of 343

To find the pair determinants of 343, we need to uncover the product the the two numbers, to gain the original number.

1 × 343 = 343

7 × 49 = 343

Therefore, the pair components are (1, 343) and (7, 49). Similarly, we deserve to consider an adverse pair components of 343, since the product of two such an adverse factors will result in a positive number.

-1 × -343 = 343

-7 × -49 = 343

Therefore, the negative pair determinants are (-1, -343) and (-7, -49).

## Prime Factorisation of 343

Prime determinants are the element numbers such as 2, 3, 5, 7, etc., the themselves have only two factors. Currently to find the prime components of a number, we require to inspect if the original number is fully divisible by the prime number or not. Thus, we will start splitting the original number by the smallest prime factor.

Step 1: Divide 343 by the the smallest prime factor.

343/7 = 49

Step 2: Again divide 49 by the the smallest prime factor.

49/7 = 7

Step 3: Again, divide 7 by 7.

7/7 = 1

Step 4: because 1 is no divisible by any type of other element apart native itself. Thus. Us will prevent our technique here. Hence,

 Prime factorisation of 343 = 7 x 7 x 7 = 73

## Solved Examples

Q.1: If 343 copies are to be distributed among 49 students in a class. How many duplicates does each college student get?

Solution: Given,

Number of duplicates = 343

Number of students in course = 49

Therefore, number of copies, each student will acquire = 343/49 = 7

Q.2: find the sum of all the components of 343.

Solution: The determinants of 343 are 1, 7, 49 and 343.

Sum = 1+7+49+343 = 400

Therefore, 400 is the required sum.

Q.3: What are the usual factors of 49 and also 343?

Answer: Both 49 and also 343 space composite numbers. Thus, their determinants are:

49 → 1, 7 and also 49

343 → 1, 7, 49 and also 343

As we deserve to see, 343 has all the factors of 49. Therefore, 1, 7 and 49 are the typical factors because that 49 and 343.