You are watching: What is the oxidation number of sulfur in na2s2o3
You currently know the O is -2 and H is -1. That method that 5H2O renders 5 x 2 x 1 + 5 x (-2) which makes 0. In Na2S2O3, three oxygen molecules carry -6, therefore the rest needs to be 6 civicpride-kusatsu.netme equilibrate. Na is, if I"m no mistaken, civicpride-kusatsu.netnstantly +1, for this reason that leaves you through 4 to add for S2. 4 separated by 2 is 2, so as such the oxidation variety of S is 2.
(Original write-up by Ivanka) You currently know that O is -2 and also H is -1. That means that 5H2O provides 5 x 2 x 1 + 5 x (-2) which makes 0. In Na2S2O3, three oxygen molecules carry -6, so the rest has to be 6 to equilibrate. Na is, if I"m not mistaken, civicpride-kusatsu.netnstantly +1, therefore that pipeline you with 4 to include for S2. 4 divided by 2 is 2, so therefore the oxidation number of S is 2.
thankyou! i didn"t recivicpride-kusatsu.netgnize that Na is civicpride-kusatsu.netnstantly +1
in reality +2 is the average oxidation number. Thiosulfate civicpride-kusatsu.netntains two S atoms, and also they space not indistinguishable (something choose +6 and also -2, imagine SO42- v one oxygen replaced by S(-2)).
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