You are watching: What is the oxidation number of sulfur in na2s2o3

You currently know the O is -2 and H is -1. That method that 5H2O renders 5 x 2 x 1 + 5 x (-2) which makes 0. In Na2S2O3, three oxygen molecules carry -6, therefore the rest needs to be 6 civicpride-kusatsu.netme equilibrate. Na is, if I"m no mistaken, civicpride-kusatsu.netnstantly +1, for this reason that leaves you through 4 to add for S2. 4 separated by 2 is 2, so as such the oxidation variety of S is 2.

(Original write-up by

**Ivanka**) You currently know that O is -2 and also H is -1. That means that 5H2O provides 5 x 2 x 1 + 5 x (-2) which makes 0. In Na2S2O3, three oxygen molecules carry -6, so the rest has to be 6 to equilibrate. Na is, if I"m not mistaken, civicpride-kusatsu.netnstantly +1, therefore that pipeline you with 4 to include for S2. 4 divided by 2 is 2, so therefore the oxidation number of S is 2.

thankyou! i didn"t recivicpride-kusatsu.netgnize that Na is civicpride-kusatsu.netnstantly +1

in reality +2 is the average oxidation number. Thiosulfate civicpride-kusatsu.netntains two S atoms, and also they space not indistinguishable (something choose +6 and also -2, imagine SO42- v one oxygen replaced by S(-2)).

Go to an initial unread

See more: 2009 Toyota Corolla Transmission Fluid Capacity, 2009 Toyota Corolla 2

A-level Chemistry assist Last-minute A-level Chemistry revision: a crammer�s overview GCSE Chemistry help GCSE Science aid