6 cards | total Attempts: 412 | created byfatimaabdul | last updated: Sep 22, 2020 | total Attempts: 412
= 101. Then, multiply the variety of gallons by the expense per gallon: 101(4.04) = 408.04. This offers the cost of gas for this auto to travel 2,727 common miles.

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When x = 3 and also y = 5, by how much does the worth of 3x2 – 2y exceed the worth of 2x2 – 3y ?
14 is the exactly answer. Once you usage x = 3 and also y = 5 in the given expressions, 3x2 – 2y = 3(3)2 – 2(5) = 27 – 10 = 17 and also 2x2 – 3y = 2(3)2 – 3(5) = 18 – 15 = 3. Then subtract 3 indigenous 17 to gain 14.
The corect answer is 7. You can solve this problem by very first subtracting 2x from every side the the equation to get 3 = x – 4. Then add 4 to every side, therefore x = 7.
42 is the correct answer because it is the largest number the is a aspect of all three numbers given. Girlfriend can find the greatest typical factor by creating out the element factorization that all 3 numbers, and then acquisition each that the common prime components to the lowest power that appears for that factor:42 = 2 × 3 × 7; 126 = 2 × 32 × 7; and 210 = 2 × 3 × 5 × 7. For this reason the greatest typical factor is 2 × 3 × 7 = 42.
Sales for a business were 3 million dollars much more the second year than the first, and also sales because that the third year were twin the sales for the second year. If sales for the third year to be 38 million dollars, what were sales, in countless dollars, for the very first year?
16 is the exactly answer. If x = sales because that the an initial year, then x + 3 = sales for the 2nd year. Because sales because that the 3rd year were dual the sales because that the 2nd year, sales for the third year = 2(x + 3). Sales because that the 3rd year were 38, therefore 2(x + 3) = 38. To solve this equation, you could first divide every side through 2 to acquire x + 3 = 19. Then, by individually 3 native both sides, x = 16.

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In the figure below, beam
was constructed starting from beam and also . By utilizing a compass, D and also G were significant equidistant indigenous E on beam and . The compass was then supplied to situate a allude F, unique from E, so that F is equidistant indigenous D and G. For every constructions characterized by the above steps, the steps of DEF and also GEF:
The exactly answer is that it is equal. If you attract line segments DF and FG, you can display DEF GEF through SSS (side-side-side congruence). So, DEF GEF due to the fact that corresponding parts of congruent triangles are congruent.