I have actually tried to know what the oxidation state because that Mn in $ceMnO4^-$ is. So much i have construed that O have actually the oxidation state the -2 so because there is 4 O the number turns to -8. What happens to the minus at O? and also what is the oxidation state because that Mn?

The sum of the oxidation claims of all of the atoms demands to same the complete charge top top the ion.

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For example, because that $ceNH4+$, if every hydrogen atom has actually an oxidation state of +1, and also the as whole charge is +1, climate we have the right to solve for the oxidation state that nitrogen:

eginaligned 4(+1) + OS_ceN &= +1\OS_ceN &= +1 -4(+1) \OS_ceN &= -3endaligned

Similarly, we have the right to do $ceSO4^2-$. If every oxygen atom has actually an oxidation state the -2, and also the as whole charge is -2, we have the right to solve for the oxidation state the sulfur:

eginaligned 4(-2) + OS_ceS &= -2\OS_ceS &= -2 -4(-2) \OS_ceS &= +6endaligned

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answered jan 6 "19 in ~ 12:28

Ben NorrisBen Norris
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Seeing as Oxygen has an oxidation state that -2 and you have actually 4 Oxygen atoms, the full charge contributed by Oxygen = -8. Because the total charge the this compound = -1, then in this case Mn = +7+7 - 8 = -1

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answered jan 6 "19 at 13:32

PeteLDWPeteLDW
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As you claimed Oxygen has actually the oxidation state that -2 so if we include up every the oxygens they have actually a -8 oxidation state.

As the oxidation state the the ion is equal to that charge, the Mn needs to "balance" the -8 to acquire it as much as -1. Thus the oxidation state that Mn in Mno4- is +7.

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answered jan 6 "19 at 13:33

LR01LR01
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