I have actually tried to know what the oxidation state because that Mn in $ceMnO4^-$ is. So much i have construed that O have actually the oxidation state the -2 so because there is 4 O the number turns to -8. What happens to the minus at O? and also what is the oxidation state because that Mn?


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The sum of the oxidation claims of all of the atoms demands to same the complete charge top top the ion.

You are watching: Oxidation state of mn in mno4

For example, because that $ceNH4+$, if every hydrogen atom has actually an oxidation state of +1, and also the as whole charge is +1, climate we have the right to solve for the oxidation state that nitrogen:

$$eginaligned 4(+1) + OS_ceN &= +1\OS_ceN &= +1 -4(+1) \OS_ceN &= -3endaligned$$

Similarly, we have the right to do $ceSO4^2-$. If every oxygen atom has actually an oxidation state the -2, and also the as whole charge is -2, we have the right to solve for the oxidation state the sulfur:

$$eginaligned 4(-2) + OS_ceS &= -2\OS_ceS &= -2 -4(-2) \OS_ceS &= +6endaligned$$


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answered jan 6 "19 in ~ 12:28
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Ben NorrisBen Norris
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Seeing as Oxygen has an oxidation state that -2 and you have actually 4 Oxygen atoms, the full charge contributed by Oxygen = -8. Because the total charge the this compound = -1, then in this case Mn = +7+7 - 8 = -1


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answered jan 6 "19 at 13:32
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PeteLDWPeteLDW
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As you claimed Oxygen has actually the oxidation state that -2 so if we include up every the oxygens they have actually a -8 oxidation state.

As the oxidation state the the ion is equal to that charge, the Mn needs to "balance" the -8 to acquire it as much as -1. Thus the oxidation state that Mn in Mno4- is +7.


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answered jan 6 "19 at 13:33
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LR01LR01
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