From layman approach, How can one calculate the possible two letter words from this 26 English letters?

There room 26 selections for the an initial letter. Because that every selection of very first letter there are 26 options for the 2nd letter. Therefore there space 26 time 26 of lock in total, or 676.

You are watching: How many two letter combinations are there

I"m assuming we"re not talking around which ones space actual words.

There are 26 possibilities because that the very first letter and also 26 for the second. Main point them and also you get 676 total feasible "words" (but this includes things like ZQ and XT.)

If you want actual words, this site claims there room 96 in the OSPD4, the Scrabble dictionary.

And if you want a better estimate, there room 6 vowels and 20 consonants (counting Y as a vowel). They deserve to go in either order (so we have the right to have words prefer OF). 6 times 20 times 2 is 240 possible words.

\$\$\beginarrayc\textalphabetical order: & aa & ba & ca & da & ea & fa & \cdots \\& abdominal & bb & cb & db & eb & fb & \cdots \\& ac & bc & cc & dc & ec & fc & \cdots \\& ad & bd & cd & dd & ed & fd & \cdots \\& ae & it is in & ce & de & ee & fe & \cdots \\& af & bf & cf & df & ef & ff & \cdots \\& ag & bg & cg & dg & eg & fg & \cdots \\& \vdots & \vdots & \vdots & \vdots & \vdots & \vdots & \endarray\$\$26 columns; 26 in every column.

More usually the formula is:

\$x^y\$

where \$x\$ is the number of items in the collection (26 feasible letters in this case), and also \$y\$ is the number of occurrences that that set of items (series that 2 letters in this case).

So,

1 letter (A) = \$26^1 = 26\$

2 letter (AA) = \$26^2 = 26*26 = 676\$

3 letters (AAA) = \$26^3 = 26 * 26 * 26 = 17,576\$

4 letters (AAAA) = \$26^4 = 26 * 26 * 26 * 26 = 456,976\$

etc.

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