Answer is: 162 g the beryllium.

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Chemical reaction: be + 2H₂O → Be(OH)₂ + H₂.m(H₂) = 36,0 g.m(Be) = ?n(H₂) = m(H₂) ÷ M(H₂) n(H₂) = 36,0 g ÷ 2 g/mol = 18 mol.from reaction: n(Be) : n(H₂) = 1 : 1.n(Be) = n(H₂) = 18 mol.m(Be) = n(Be) · M(Be).n(Be) = 18 mol · 9 g/mol = 162 g.

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