How lengthy does that take for the last automobile to pertained to rest? A train is traveling up a 3.2° incline at a speed of 3.95 m/s when the last automobile breaks totally free and begins to coast. __________________s
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You must use the following equation because that uniformly increased motion such that:

`v = v_0 + a*t`

`v` to represent the final speed

`v_0` represents the early speed

because the trouble provides the initial rate of `3.95 m/s` , you require to uncover the time necessary for the car to come...

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You need to use the following equation because that uniformly increased motion together that:

`v = v_0 + a*t`

`v` to represent the final speed

`v_0` represents the initial speed

Since the difficulty provides the initial rate of `3.95 m/s` , you need to discover the time essential for the automobile to concerned rest, considering the last speed same to 0 such that:

`0 = 3.95 +a*t => at = -3.95`

You may uncover the acceleration a using the information noted by the problem that the train is traveling up a `3.2^o` incline together that:

`g*sin3.2^o = a => 9.8*0.055 = a => a = 0.547 m/s^2`

Substituting `0.547` because that a in equation `a*t = -3.95` yields:

`a*t = -3.95 => t = -3.95/a => t = -3.95/0.547 => t =7.22 s`

Hence, evaluating the time needed for the last vehicle to come to the rest yields `t = 7.22 s` .

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