Minor arc QV is 80 degrees because it adds come minor arc VU = 100 to get 80+100 = 180. Note exactly how angle QPU = 180, due to the fact that it"s a directly line and also QU is a diameter that the circle.

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Add increase the young arcs

TUUVVQ

to get: 44+100+80 = 224

This method arc TUQ is 224 degrees. Inscribed edge QZT subtends arc TUQ. Use the inscribed angle theorem come say that the inscribed angle is half of the arc it cuts off.

angle QZT = (arc TUQ)/2

angle QZT = 224/2

angle QZT = 112 levels




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