based on an experiment, a equipment that consisted of $\ceCu^2+$ created a precipitate with $\ceNaOH$. Is this exactly how you compose the equation?

$$\ce2NaOH + Cu^2+ -> Cu(OH)2 + 2Na+$$

On the experiment: equipment A is blended with NaOH (solution rotate white). Utilizing a flame test solution A is color green. I figured systems A has actually $\ceCu^2+$ ion.

You are watching: Cuso4 + naoh net ionic equation


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Yes, the reaction is correct yet it might be preferable come either incorporate all or no spectator ions.Use one of two people a network ionic equations (omit the Na+), molecular equation (include the copper compound full) or finish ionic equation.

For example, if the link is copper sulphate the equations would certainly be (without states)

Net ionic$$\ceCu^2++\ce2OH^-->Cu(OH)_2$$Molecular equation$$\ceCuSO_4+\ce2NaOH->Cu(OH)_2+\ceNa_2SO_4$$Complete Ionic Equation$$\ceCu^2+ +SO_4^2-+\ce2Na^+ +2OH^-->Cu(OH)_2+\ce2Na^+ +SO_4^2-$$

Edit

In the instance where you don"t recognize what copper link it is, use a net ionic equation. Together a side note, copper hydroxide is not white. You can want to inspect your calculations.

If you"re wonder what it is, inspect what other compounds will certainly emit green.


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edited Dec 19 "16 in ~ 1:08
answered Dec 19 "16 at 1:03
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